The bilateral Laplace transform of a function
$$f\left( t \right) = \left\{ {\matrix{
{1,} & {{\rm{if}}\,a \le t \le b} \cr
0 & {{\rm{otherwise}}} \cr
} } \right.$$ is
A. $${{a - b} \over s}$$
B. $${{{e^z}\left( {a - b} \right)} \over s}$$
C. $${{{e^{ - as}} - {e^{ - bs}}} \over s}$$
D. $${{{e^{ - \left( {a - b} \right)}}} \over s}$$
Answer: Option C
This Question Belongs to Electronics And Communications Engineering >> Signal Processing
Join The Discussion