The brake power (B.P.) of the engine is given by (where W = Brake load or dead load in newtons, $$l$$ = Length of arm in meters, N = Speed of engine in r.p.m., S = Spring balance reading in newtons, D = Diameter of brake drum in meters and d = Diameter of rope in meters)
A. $${\text{B}}{\text{.P}}{\text{.}} = \frac{{{\text{W}}l \times 2\pi {\text{N}}}}{{60}}{\text{ watts}}$$
B. $${\text{B}}{\text{.P}}{\text{.}} = \frac{{\left( {{\text{W}} - {\text{S}}} \right)\pi {\text{DN}}}}{{60}}{\text{ watts}}$$
C. $${\text{B}}{\text{.P}}{\text{.}} = \frac{{\left( {{\text{W}} - {\text{S}}} \right)\pi \left( {{\text{D}} + {\text{d}}} \right){\text{N}}}}{{60}}{\text{ watts}}$$
D. All of these
Answer: Option D
Solution (By Examveda Team)
The brake power (B.P.) of the engine is given by- $${\text{B}}{\text{.P}}{\text{.}} = \frac{{{\text{W}}l \times 2\pi {\text{N}}}}{{60}}{\text{ watts}}$$
- $${\text{B}}{\text{.P}}{\text{.}} = \frac{{\left( {{\text{W}} - {\text{S}}} \right)\pi {\text{DN}}}}{{60}}{\text{ watts}}$$
- $${\text{B}}{\text{.P}}{\text{.}} = \frac{{\left( {{\text{W}} - {\text{S}}} \right)\pi \left( {{\text{D}} + {\text{d}}} \right){\text{N}}}}{{60}}{\text{ watts}}$$
Where W = Brake load or dead load in newtons, $$l$$ = Length of arm in meters, N = Speed of engine in r.p.m., S = Spring balance reading in newtons, D = Diameter of brake drum in meters and d = Diameter of rope in meters.
Join The Discussion