The capacity of a band-limited additive white Gaussian noise (AWGN) channel is given by $$C = W{\log _2}\left( {1 + \frac{P}{{{\sigma ^2}W}}} \right)$$ bits per second (bps), where W is the channel bandwidth, P is the average power received and σ2 is the one-sided power spectral density of the AWGN.
For a fixed $$\frac{P}{{{\sigma ^2}}} = 1000,$$ the channel capacity (in kbps) with infinite bandwidth $$\left( {W \to \infty } \right)$$ is approximately
A. 1.44
B. 1.08
C. 0.72
D. 0.36
Answer: Option A
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