The capacity of a band-limited additive white Gaussian noise (AWGN) channel is given by $$C = W\,{\log _2}\left( {1 + \frac{P}{{{\sigma ^2}W}}} \right)$$     bits per second (bps), where W is the channel bandwidth, P is the average power received and σ² is the one-sided power spectral density of the AWGN. For a fixed $$\frac{P}{{{\sigma ^2}}} = 1000,$$   the channel capacity (in kbps) with infinite bandwidth (W → ∞) is approximately

A. 1.44

B. 1.08

C. 0.72

D. 0.36

Answer: Option A