The capacity of a band-limited additive white Gaussian noise (AWGN) channel is given by $$C = W\,{\log _2}\left( {1 + \frac{P}{{{\sigma ^2}W}}} \right)$$ bits per second (bps), where W is the channel bandwidth, P is the average power received and σ2 is the one-sided power spectral density of the AWGN. For a fixed $$\frac{P}{{{\sigma ^2}}} = 1000,$$ the channel capacity (in kbps) with infinite bandwidth (W → ∞) is approximately
A. 1.44
B. 1.08
C. 0.72
D. 0.36
Answer: Option A
This Question Belongs to Electronics And Communications Engineering >> Information Theory And Coding
Join The Discussion