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Strength of Materials in ME
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The change in the unit volume of a material under tension with increase in its Poisson's ratio will

Answer & Solution
Correct Answer: Option B
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1 Comment
Atif Muneer
Atif Muneer 5 years ago
The poisson's ratio is related to modulus of elasticity as Y=3B(1−2σ). Since stress is same for Y and B, we get, dL/L=dV/3V(1−2σ)⟹dV=3V(dL/L)(1−2σ)
As σ is increased, dV decreases. 

The correct option is (b)