The channel capacity of an ideal AWGN channel with infinite bandwidth is approximated as (where S is average signal power and $$\frac{\eta }{2}$$ is the double sided power spectral density of white Gaussian noise)
A. $$1.44\frac{{\text{S}}}{\eta }{\text{b/s}}$$
B. $$\frac{{\text{S}}}{{1.44\eta }}{\text{b/s}}$$
C. $$1.44\frac{\eta }{{\text{S}}}{\text{b/s}}$$
D. $$2.88\frac{{\text{S}}}{\eta }{\text{b/s}}$$
Answer: Option A
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