The C.O.P. of a refrigerator working on a reversed Carnot cycle is (where T1 = Lowest absolute temperature and T2 = Highest absolute temperature)
A. $$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2} - {{\text{T}}_1}}}$$
B. $$\frac{{{{\text{T}}_2} - {{\text{T}}_1}}}{{{{\text{T}}_1}}}$$
C. $$\frac{{{{\text{T}}_1} - {{\text{T}}_2}}}{{{{\text{T}}_1}}}$$
D. $$\frac{{{{\text{T}}_2}}}{{{{\text{T}}_2} - {{\text{T}}_1}}}$$
Answer: Option A
Solution (By Examveda Team)
The C.O.P. of a refrigerator working on a reversed Carnot cycle is $$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2} - {{\text{T}}_1}}}$$Where
T1 = Lowest absolute temperature,
T2 = Highest absolute temperature
This Question Belongs to Mechanical Engineering >> Refrigeration And Air Conditioning
Join The Discussion