The C.O.P. of an absorption type refrigerator is given by (where T₁ = Temperature at which the working substance receives heat, T₂ = Temperature of cooling water and T₃ = Evaporator temperature)

A) $$\frac{{{{\text{T}}_1}\left( {{{\text{T}}_2} - {{\text{T}}_3}} \right)}}{{{{\text{T}}_3}\left( {{{\text{T}}_1} - {{\text{T}}_2}} \right)}}$$ B) $$\frac{{{{\text{T}}_3}\left( {{{\text{T}}_1} - {{\text{T}}_2}} \right)}}{{{{\text{T}}_1}\left( {{{\text{T}}_2} - {{\text{T}}_3}} \right)}}$$ C) $$\frac{{{{\text{T}}_1}\left( {{{\text{T}}_1} - {{\text{T}}_2}} \right)}}{{{{\text{T}}_3}\left( {{{\text{T}}_2} - {{\text{T}}_3}} \right)}}$$ D) $$\frac{{{{\text{T}}_3}\left( {{{\text{T}}_2} - {{\text{T}}_3}} \right)}}{{{{\text{T}}_1}\left( {{{\text{T}}_1} - {{\text{T}}_2}} \right)}}$$

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Correct Answer: Option B

The C.O.P. of an absorption type refrigerator is given by $$\frac{{{{\text{T}}_3}\left( {{{\text{T}}_1} - {{\text{T}}_2}} \right)}}{{{{\text{T}}_1}\left( {{{\text{T}}_2} - {{\text{T}}_3}} \right)}}$$
(Where T₁ = Temperature at which the working substance receives heat, T₂ = Temperature of cooling water and T₃ = Evaporator temperature)

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The C O P of an absorption type refrigerator is given...

The C.O.P. of an absorption type refrigerator is given by (where T1 = Temperature at which the working substance receives heat, T2 = Temperature of cooling water and T3 = Evaporator temperature)

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The C.O.P. of an absorption type refrigerator is given by (where T₁ = Temperature at which the working substance receives heat, T₂ = Temperature of cooling water and T₃ = Evaporator temperature)