The cost of an article was Rs.75. The cost was first increased by 20% and later on it was reduced by 20%. The present cost of the article is:
A. Rs. 72
B. Rs. 60
C. Rs. 75
D. Rs. 76
Answer: Option A
Solution(By Examveda Team)
Initial Cost = Rs. 75 After 20% increase in the cost, it becomes, (75 + 20% of 75) = Rs. 90 Now, Cost is decreased by 20%, So cost will become, (90 - 20% of 90) = Rs. 72 So, present cost is Rs. 72This Question Belongs to Arithmetic Ability >> Percentage
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A. $$\frac{1}{4}$$
B. $$\frac{1}{3}$$
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Cost=75
Increased 20%= 20/100×75=15
So, 75+15=90
Now cost is decreased by 20%=20/100×90=18
Therefore present cost=90-18 =72ans
How to find (90-20% of 90)=?
20%=1/5
20%=1/5
5 6
5 4
25 24
*3 *3
75 72 ans