The determinant \[\left| {\begin{array}{*{20}{c}} {1 + {\text{b}}}&{\text{b}}&1 \\ {\text{b}}&{1 + {\text{b}}}&1 \\ 2&{2{\text{b}}}&1 \end{array}} \right|\] equals to
A. 0
B. 2b(b - 1)
C. 2(1 - b) (1 + 2b)
D. 3b(1 + b)
Answer: Option A
Related Questions on Linear Algebra
A. 3, 3 + 5j, 6 - j
B. -6 + 5j, 3 + j, 3 - j
C. 3 + j, 3 - j, 5 + j
D. 3, -1 + 3j, -1 - 3j
A. 1024 and -1024
B. 1024√2 and -1024√2
C. 4√2 and -4√2
D. 512√2 and -512√2

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