The difference of pressure between the inside and outside of a liquid drop is

A. $${\text{p}} = {\text{T}} \times {\text{r}}$$

B. $${\text{p}} = \frac{{\text{T}}}{{\text{r}}}$$

C. $${\text{p}} = \frac{{\text{T}}}{{2{\text{r}}}}$$

D. $${\text{p}} = \frac{{2{\text{T}}}}{{\text{r}}}$$

Answer: Option D

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Comments ( 2 )

  1. Sreenu Sreenu
    Sreenu Sreenu :
    3 years ago

    If T is the surface tension of the liquid, the force due to surface tension acting downward along the circumference of the circle ABCD is T 2πr.
    At equilibrium, Pπr 2 = T 2πr
    P = 2T/r

  2. Fajar Khan
    Fajar Khan :
    4 years ago


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