The discharge over a rectangular weir, considering the velocity of approach, is (where H1 = H + Ha) (H1 = Total height of water above the weir, H = Height of water over the crest of the weir and Ha = Height of water due to velocity of approach)

23C_d Lsqrt 2g [ H_1^32 - H_a^32 ]

This question belongs to Mechanical Engineering Hydraulics And Fluid Mechanics In ME

Hydraulics and Fluid Mechanics in ME

The discharge over a rectangular weir, considering the velocity of approach, is (where H₁ = H + H_a)
(H₁ = Total height of water above the weir, H = Height of water over the crest of the weir and H_a = Height of water due to velocity of approach)

A) $$\frac{2}{3}{{\text{C}}_{\text{d}}} \times {\text{L}}\sqrt {2{\text{g}}} \left[ {{{\text{H}}_1} - {{\text{H}}_{\text{a}}}} \right]$$ B) $$\frac{2}{3}{{\text{C}}_{\text{d}}} \times {\text{L}}\sqrt {2{\text{g}}} \left[ {{\text{H}}_1^{\frac{3}{2}} - {\text{H}}_{\text{a}}^{\frac{3}{2}}} \right]$$ C) $$\frac{2}{3}{{\text{C}}_{\text{d}}} \times {\text{L}}\sqrt {2{\text{g}}} \left[ {{\text{H}}_1^2 - {\text{H}}_{\text{a}}^2} \right]$$ D) $$\frac{2}{3}{{\text{C}}_{\text{d}}} \times {\text{L}}\sqrt {2{\text{g}}} \left[ {{\text{H}}_1^{\frac{5}{2}} - {\text{H}}_{\text{a}}^{\frac{5}{2}}} \right]$$

Answer & Solution

Correct Answer: Option B

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