The discharge through a small rectangular orifice is given by (where Cd = Coefficient of discharge for the orifice, a = Cross-sectional area of the orifice, h = Height of the liquid above the centre of the orifice)
A. $${\text{Q}} = {{\text{C}}_{\text{d}}} \times {\text{a}} \times \sqrt {2{\text{gh}}} $$
B. $${\text{Q}} = \frac{2}{3}{{\text{C}}_{\text{d}}} \times {\text{a}} \times {\text{h}}$$
C. $${\text{Q}} = \frac{{{{\text{C}}_{\text{d}}} \times {\text{a}}}}{{\sqrt {2{\text{gh}}} }}$$
D. $${\text{Q}} = \frac{{3{{\text{C}}_{\text{d}}} \times {\text{a}}}}{{\sqrt {2{\text{h}}} }}$$
Answer: Option A
This Question Belongs to Mechanical Engineering >> Hydraulics And Fluid Mechanics In ME
The Small rectangular orifice discharge = 2/3 x Cd x a x root 2gh.