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Linear Algebra
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The equation \[\left[ {\begin{array}{*{20}{c}} 2&{ - 2} \\ 1&{ - 1} \end{array}} \right]\left[ {\begin{array}{*{20}{c}} {{{\text{x}}_1}} \\ {{{\text{x}}_2}} \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} 0 \\ 0 \end{array}} \right]\]    has

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Correct Answer: Option D
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