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The equation of motion for a single degree of freedom system...

This question belongs to Mechanical Engineering Theory Of Machine
Theory of Machine
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The equation of motion for a single degree of freedom system with viscous damping is $$4\frac{{{{\text{d}}^2}{\text{x}}}}{{{\text{d}}{{\text{t}}^2}}} + 9\frac{{{\text{dx}}}}{{{\text{dt}}}} + 16{\text{x}} = 0.$$     The damping ratio of the system is

Answer & Solution
Correct Answer: Option C
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3 Comments
KARTAVYA SAGAR
KARTAVYA SAGAR 5 years ago
Zeta = c / [2 (m. k)^(1/2)]
= 9 / [ 2(4*16)^(1/2)]
= 9 / 2 (8)
= 9 / 16
Madhavan Palmani
Madhavan Palmani 7 years ago
Given:

m = 4, c = 9 & s = 16.

Damping factor = (c/cc).

w = sqr of s/m = 2.

cc = 2mw = 2*4*2 = 16.

c/cc = 9/16.
Shravan Gupta
Shravan Gupta 7 years ago
Plz explain it
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