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The equation of motion for a single degree of freedom system with viscous damping is $$4\frac{{{{\text{d}}^2}{\text{x}}}}{{{\text{d}}{{\text{t}}^2}}} + 9\frac{{{\text{dx}}}}{{{\text{dt}}}} + 16{\text{x}} = 0.$$     The damping ratio of the system is

A. $$\frac{9}{8}$$

B. $$\frac{9}{{8\sqrt 2 }}$$

C. $$\frac{9}{{16}}$$

D. $$\frac{9}{{128}}$$

Answer: Option C


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Comments ( 3 )

  1. KARTAVYA SAGAR
    KARTAVYA SAGAR :
    3 years ago

    Zeta = c / [2 (m. k)^(1/2)]
    = 9 / [ 2(4*16)^(1/2)]
    = 9 / 2 (8)
    = 9 / 16

  2. Madhavan Palmani
    Madhavan Palmani :
    4 years ago

    Given:

    m = 4, c = 9 & s = 16.

    Damping factor = (c/cc).

    w = sqr of s/m = 2.

    cc = 2mw = 2*4*2 = 16.

    c/cc = 9/16.

  3. Shravan Gupta
    Shravan Gupta :
    4 years ago

    Plz explain it

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