The greatest number by which the product of three consecutive multiples of 3 is always divisible is :
A. 54
B. 81
C. 162
D. 243
Answer: Option C
Solution(By Examveda Team)
Three consecutive multiples of 3 are 3m, 3(m + 1) and 3(m + 2)Their product = 3m × 3(m + 1) × 3(m + 2)
= 27 × m × (m + 1) × (m + 2)
Putting m = 1, this product is (27 × 1 × 2 × 3) = 162
So, this product is always divisible by 162
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
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