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This question belongs to Arithmetic Ability Number System
Number System
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The greatest number which will divides: 4003, 4126 and 4249, leaving the same remainder in each case:

Answer & Solution
Correct Answer: Option B
Rule- Greatest number with which if we divide P, Q, R and it leaves same remainder in each case. Number is of form = HCF of (P - Q), (P - R)
Therefore, HCF of (4126 - 4003), (4249 - 4003) = HCF of 123, 246 = 41.[Taken for Positive result].

Detailed Explanation:
The numbers can be written as,
4003 = AX + P where P = Remainder
4126 = BX + P
4249 = CX + P
(B - A) × X = 123
(C - B) × X = 246
Thus the X is factor of 123 and 246
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10 Comments
Amit Singh
Amit Singh 7 years ago
4003 is a prime number, divisible by 1 or itself only. So the answer is d) none of these
Insane Engineer
Insane Engineer 8 years ago
Since HCF is 1
Hence answer is none of these
Insane Engineer
Insane Engineer 8 years ago
Since HCF is 1
Hence is none of these
Saswat Mishra
Saswat Mishra 9 years ago
HCF is 1
Kumar Chandan
Kumar Chandan 11 years ago
Answer solution has been corrected now. Actually, 41 is factor of 123 so answer would be 41.
Aarushi
Aarushi 11 years ago
The answer should be greatest no, on dividing the numbers by 123, they leave the same remainder
Aarushi
Aarushi 11 years ago
41 does not divide any of the given numbers, how can it be the HCF
Vichu
Vichu 11 years ago
right answer will be 123
Gaurav
Gaurav 11 years ago
Right answer is 43
Mohan
Mohan 11 years ago
4249-4003=246,4249-4126=123, hence the Number are 246 and 123. 246=2*3*41,123=3*41. actually we found the hcf of both is 41*3=123. but by the options are given in the the two digit so the answer will be 41.