The greatest number which will divides: 4003, 4126 and 4249, leaving the same remainder in each case:
A. 43
B. 41
C. 45
D. None of these
Answer: Option B
Solution(By Examveda Team)
Rule- Greatest number with which if we divide P, Q, R and it leaves same remainder in each case. Number is of form = HCF of (P - Q), (P - R) Therefore, HCF of (4126 - 4003), (4249 - 4003) = HCF of 123, 246 = 41.[Taken for Positive result]. Detailed Explanation: The numbers can be written as, 4003 = AX + P where P = Remainder 4126 = BX + P 4249 = CX + P (B - A) × X = 123 (C - B) × X = 246 Thus the X is factor of 123 and 246This Question Belongs to Arithmetic Ability >> Number System
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Comments ( 10 )
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
4003 is a prime number, divisible by 1 or itself only. So the answer is d) none of these
Since HCF is 1
Hence answer is none of these
Since HCF is 1
Hence is none of these
HCF is 1
Answer solution has been corrected now. Actually, 41 is factor of 123 so answer would be 41.
The answer should be greatest no, on dividing the numbers by 123, they leave the same remainder
41 does not divide any of the given numbers, how can it be the HCF
right answer will be 123
Right answer is 43
4249-4003=246,4249-4126=123, hence the Number are 246 and 123. 246=2*3*41,123=3*41. actually we found the hcf of both is 41*3=123. but by the options are given in the the two digit so the answer will be 41.