The HCF of 2472, 1284 and a third number 'N' is 12. If their LCM is 23 × 32 × 5 × 103 × 107, then the number 'N' is:
A. 22 × 32 × 7
B. 22 × 33 × 10
C. 22 × 32 × 5
D. None of these
Answer: Option D
Solution(By Examveda Team)
We have,HCF of the numbers × LCM of the numbers = Multiplication of the numbers.
(12) × (23 × 32 × 5 × 103 × 107) = 2472 × 1284 × N
Hence,
N = $$\frac{{\{ \left( {12} \right) \times \left( {{2^3} \times {3^2} \times 5 \times 103 \times 107} \right)\} }}{{2472 \times 1284}}$$
Or, N = 3 × 5
This Question Belongs to Arithmetic Ability >> Number System
Join The Discussion
Comments ( 8 )
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
I got it.. option c will be the answer
answer is c
taken the lcm of given three numbers is
lcm=12*206*107*y (N=12*y)
and given lcm is 2^3*3^2*5*103*107
and equating both lcms and get the value of y is 15
so the third number is 2^2*3^2*5
Lcm × (hcf ki power of n-1) = multiple of numbers. Here, n=total number
Solution for this question = 2³×3²×5×103×107×12²=2472×1284×b
Find from here the value of b.... Here, value of b is our answer. It is also option C
If N is 3*5. How HCF can be 12
Answer is C - 180.
Right all the factors for all the values. Figure out the GCD from that.
Then the remaining values that are not present in LCM has to be present in the value N.
Formula works for any number of numbers.
can you give your explanation for this question? @Sakthivel
your answer is wrong.This formula will only work for two numbers
but there is no option 15 but u have mentioned option c is the right one.Could you explain me?