Examveda
Examveda

The H.C.F of 4 × 27 × 3125, 8 × 9 × 25 × 7 and 16 × 81 × 5 × 11 × 49 is = ?

A. 180

B. 360

C. 540

D. 1260

Answer: Option A

Solution(By Examveda Team)

4 × 27 × 3125 = 22 × 33 × 55
8 × 9 × 25 × 7 = 23 × 32 × 52 × 7
16 × 81 × 5 × 11 × 49 = 24 × 34 × 5 × 11 × 72
∴ H.C.F = 22 × 32 × 5 = 180

This Question Belongs to Arithmetic Ability >> Problems On H.C.F And L.C.M

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