The HCF of $$\frac{9}{{10}}{\text{,}}\frac{{12}}{{25}}{\text{,}}\frac{{18}}{{35}}$$ and $$\frac{{21}}{{40}}$$ is = ?
A. $$\frac{3}{5}$$
B. $$\frac{{252}}{5}$$
C. $$\frac{3}{{1400}}$$
D. $$\frac{{63}}{{700}}$$
Answer: Option C
Solution (By Examveda Team)
$$\eqalign{ & {\text{Required HCF }} \cr & {\text{ = }}\frac{{{\text{HCF of 9,12,18,21}}}}{{{\text{LCM of 10,25,35,40}}}} \cr & = \frac{3}{{1400}} \cr} $$This Question Belongs to Arithmetic Ability >> Problems On H.C.F And L.C.M
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