The HCF of $$\frac{9}{{10}}{\text{,}}\frac{{12}}{{25}}{\text{,}}\frac{{18}}{{35}}$$   and $$\frac{{21}}{{40}}$$ is = ?

A. $$\frac{3}{5}$$

B. $$\frac{{252}}{5}$$

C. $$\frac{3}{{1400}}$$

D. $$\frac{{63}}{{700}}$$

Answer: Option C

Solution(By Examveda Team)

$$\eqalign{ & {\text{Required HCF }} \cr & {\text{ = }}\frac{{{\text{HCF of 9,12,18,21}}}}{{{\text{LCM of 10,25,35,40}}}} \cr & = \frac{3}{{1400}} \cr} $$