The impulse response h[n] of a linear time invariant system is given as
$$h\left[ n \right] = \left\{ {\matrix{
{ - 2\sqrt 2 ,} \cr
{4\sqrt 2 ,} \cr
{0,} \cr
} } \right.\matrix{
{n = 1, - 1} \cr
{n = 2, - 2} \cr
{{\rm{otherwise}}} \cr
} $$
If the input to the above system is the sequence $${e^{{{j\pi n} \over 4}}},$$ the output is
A. $$4\sqrt 2 {e^{{{j\pi n} \over 4}}}$$
B. $$4\sqrt 2 {e^{ - {{j\pi n} \over 4}}}$$
C. $$4{e^{{{j\pi n} \over 4}}}$$
D. $$ - 4{e^{{{j\pi n} \over 4}}}$$
Answer: Option D
This Question Belongs to Electronics And Communications Engineering >> Signal Processing
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