The inherent characteristic of an equal percentage valve relating flow rate 'q' with valve stem movement 'x' are described by the equation
A. $$\frac{{{\text{dq}}}}{{{\text{dx}}}} = {\text{K}}$$
B. $$\frac{{{\text{dq}}}}{{{\text{dx}}}} = {\text{K}} \times {\text{q}}$$
C. $$\frac{{{\text{dq}}}}{{{\text{dx}}}} = \frac{{\text{K}}}{{\text{q}}}$$
D. $$\frac{{{\text{dq}}}}{{{\text{dx}}}} = {\text{K}} \times {{\text{q}}^2}$$
Answer: Option A
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