The input to a channel is a band-pass signal. It is obtained by linearly modulating a sinusoidal carrier with a single-tone signal. The output of the channel due to this input is given by Y(t) = $$\left( {\frac{1}{{100}}} \right)$$ cos(100t - 10-6)cos(106t - 1.56)
The group delay (tg) and the phase delay (tp) in seconds, of the channel are
A. tg = 1.56, tp = 10-6
B. tg = 1.56 (108), tp = 10-6
C. tg = 10-8, tp = 1.56(10-6)
D. tg = 10-6, tp = 1.56
Answer: Option C
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