The input to a channel is a bandpass signal. It is obtained by linearly modulating a sinusoidal carrier with a single-tone signal. The output of the channel due to this input is given by
$$y\left( t \right) = \left( {{1 \over {100}}} \right)\cos \left( {100t - {{10}^{ - 6}}} \right)\cos \left( {{{10}^6}t - 1.56} \right)$$
The group delay (t_g) and the phase delay (t_p) in seconds, of the channel are

A. t_g = 10^-6, t_p = 1.56

B. t_g = 1.56, t_p = 10^-6

C. t_g = 10^-8, t_p = 1.56 × 10^-6

D. t_g = 10⁸, t_p = 1.56

Answer: Option D