The inverse of the 2 × 2 matrix \[\left[ {\begin{array}{*{20}{c}} 1&2 \\ 5&7 \end{array}} \right]\] is
A. \[\frac{1}{3}\left[ {\begin{array}{*{20}{c}} { - 7}&2 \\ 5&{ - 1} \end{array}} \right]\]
B. \[\frac{1}{3}\left[ {\begin{array}{*{20}{c}} 7&2 \\ 5&1 \end{array}} \right]\]
C. \[\frac{1}{3}\left[ {\begin{array}{*{20}{c}} 7&{ - 2} \\ { - 5}&1 \end{array}} \right]\]
D. \[\frac{1}{3}\left[ {\begin{array}{*{20}{c}} { - 7}&{ - 2} \\ { - 5}&{ - 1} \end{array}} \right]\]
Answer: Option A
This Question Belongs to Engineering Maths >> Linear Algebra
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