The ionic strength of 0.05 M CaCl2 solution will be
A. 0.3
B. 0.15
C. 0.4
D. 0.6
Answer: Option B
Solution (By Examveda Team)
CaCl2 solution has 2 ions of chlorine.Stoichiometric factor 2 of Cl-
Based on the equation, a 0.05 M CaCl2 solution has an ionic strength of
I = 3 × 0.05 M
= 0.15 M
This Question Belongs to Agriculture >> Soil Science
Join The Discussion