The ionic strength of 0.05 M CaCl₂ solution will be

A. 0.3

B. 0.15

C. 0.4

D. 0.6

Answer: Option B

Solution(By Examveda Team)

CaCl₂ solution has 2 ions of chlorine.
Stoichiometric factor 2 of Cl^-
Based on the equation, a 0.05 M CaCl₂ solution has an ionic strength of
I = 3 × 0.05 M
  = 0.15 M