The IR stretching frequencies (cm-1) for the compound X are as follows: 3300-3500 (s, br); 3000 (m); 2225 (s); 1680 (s).
The correct assignment of the absorption bands is
A. \[{\overline {\rm{V}} _{\left( {{\rm{OH}}} \right)}}\] = 3300-3500; \[{\overline {\rm{V}} _{\left( {{\rm{CH}}} \right)}}\] = 3000; \[{\overline {\rm{V}} _{\left( {{\rm{CN}}} \right)}}\] = 2225; \[{\overline {\rm{V}} _{\left( {{\rm{CO}}} \right)}}\] = 1680
B. \[{\overline {\rm{V}} _{\left( {{\rm{OH}}} \right)}}\] = 3000; \[{\overline {\rm{V}} _{\left( {{\rm{CH}}} \right)}}\] = 3300-3500; \[{\overline {\rm{V}} _{\left( {{\rm{CN}}} \right)}}\] = 2225; \[{\overline {\rm{V}} _{\left( {{\rm{CO}}} \right)}}\] = 1680
C. \[{\overline {\rm{V}} _{\left( {{\rm{OH}}} \right)}}\] = 3300-3500; \[{\overline {\rm{V}} _{\left( {{\rm{CH}}} \right)}}\] = 3000; \[{\overline {\rm{V}} _{\left( {{\rm{CN}}} \right)}}\] = 1680; \[{\overline {\rm{V}} _{\left( {{\rm{CO}}} \right)}}\] = 2225
D. \[{\overline {\rm{V}} _{\left( {{\rm{OH}}} \right)}}\] = 3000; \[{\overline {\rm{V}} _{\left( {{\rm{CH}}} \right)}}\] = 3300-3500; \[{\overline {\rm{V}} _{\left( {{\rm{CN}}} \right)}}\] = 1680; \[{\overline {\rm{V}} _{\left( {{\rm{CO}}} \right)}}\] = 2225
Answer: Option A
This Question Belongs to Engineering Chemistry >> Basics Of Organic Reaction Mechanism
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