The Laplace transform of exp(at), where a > 0, is defined only for the Laplace parameter, s > a since
A. The function is exponential
B. The Laplace transform of integral of exp(at) has finite values only for s > a
C. The Laplace transform integral of exp(at) has initial values only for s > a
D. The function exp(at) is piece-wise continuous only for s > a
Answer: Option B
This Question Belongs to Chemical Engineering >> Process Control And Instrumentation
The solution of the function f(x) =0 using newtons raphson method fails if f(x) is near or equal to
The Laplace transformation of the function eat is