The largest 4-digit number exactly divisible by each of 12 15...

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The largest 4-digit number exactly divisible by each of 12, 15, 18 and 27 is?

A. 9690

B. 9720

C. 9930

D. 9960

Answer: Option B

Solution(By Examveda Team)

LCM of (12, 15, 18, 27)
⇒ 4 × 3 × 5 × 3 × 3 = 540
largest 4-digits number = 9999 on dividing by 540 to number = $$\frac{{9999}}{{540}}$$
remainder = 279
Required number = 9999 - 279 = 9720

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The largest 4-digit number exactly divisible by each of 12 15...

The largest 4-digit number exactly divisible by each of 12, 15, 18 and 27 is?

Solution(By Examveda Team)

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