Solution (By Examveda Team)
$$\eqalign{
& {\text{Let HCF = }}x \cr
& {\text{LCM = 44}}x \cr
& {\text{given HCF + LCM}} \cr
& = 44x + x = 45x \cr
& 45x = {\text{ }}112{\text{5}} \cr
& x = \frac{{1125}}{{45}} = 25 \cr
& \therefore {\text{HCF}} = {\text{25}} \cr
& {\text{LCM = 25}} \times {\text{44}} \cr
& {\text{also given that one number}} \cr
& {\text{ = 25}} \cr
& {\text{Let another number = }}y \cr
& \therefore 25y = 25 \times 25 \times 44 \cr
& y = \frac{{25 \times 25 \times 44}}{{25}} \cr
& y = 1100 \cr} $$
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