The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:
A. 1677
B. 1683
C. 2523
D. 3363
Answer: Option B
Solution(By Examveda Team)
L.C.M. of 5, 6, 7, 8 = 840.∴ Required number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2
∴ Required number = (840 x 2 + 3) = 1683
This Question Belongs to Arithmetic Ability >> Problems On H.C.F And L.C.M
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Related Questions on Problems on H.C.F and L.C.M
K=2 ?
K=2 ?
L.C.M. of 5, 6, 7, 8 = 840.
now, hit and try.
(840*1)+3 not divided by 9
(840*2)+3 divided by 9
therefore option B.