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The least value of tan2x + cot2x is?
Answer & Solution
Correct Answer:
Option
B
$${\text{ta}}{{\text{n}}^2}x + {\text{co}}{{\text{t}}^2}x$$
We know that the value of tan2x and cot2x is minimum at 45°
$$\eqalign{ & \therefore {\text{ta}}{{\text{n}}^2}{45^ \circ } + {\text{co}}{{\text{t}}^2}{45^ \circ } \cr & = 1 + 1 \cr & = 2 \cr} $$
We know that the value of tan2x and cot2x is minimum at 45°
$$\eqalign{ & \therefore {\text{ta}}{{\text{n}}^2}{45^ \circ } + {\text{co}}{{\text{t}}^2}{45^ \circ } \cr & = 1 + 1 \cr & = 2 \cr} $$
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