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The length, breadth and height of a room in the shape of a cuboid are increased by 10%, 20% and 50% respectively. Find the percentage change in the volume of the cuboid.

Answer & Solution
Correct Answer: Option D
Let each side of the cuboid be 10 unit initially.
Initial Volume of the cuboid,
= length * breadth * height = 10 × 10 × 10 = 1000 cubic unit.
After increment dimensions become,
Length = (10 + 10% of 10) = 11 unit.
Breadth = (10 + 20% of 10) = 12 unit.
Height = (10 + 50% of 10) = 15 unit.
Now, present volume = 11 × 12 × 15 = 1980 cubic unit.
Increase in volume = 1980 - 1000 = 980 cubic unit.
% increase in volume = $$\frac{{980}}{{1000}} \times 100 = 98\% $$

Mind Calculation Method:
100 == 50%↑(height effects) ==> 150 == 20%↑(breadth) ==> 180 == 10%↑(length effects) ==> 198
Change in volume = 98%
[We can take net percentage change in any order]
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3 Comments
Tanim Intesar
Tanim Intesar 2 years ago
150 ==20%| =180 ==10%|=198
198-100= 98
Rakesh Kumar
Rakesh Kumar 2 years ago
Suppose all side 10 unit
We know= l×b×h = 10×10×10= 1000
Length =11
B=12
H=15
=1980
Change volume= present -initial= 1980-1000= 980
980/1000×100= 98%

Thanks
Ratnesh Pandey
Ratnesh Pandey 11 years ago
How a cuboid's length breadth and height can be same.
It will become cube.