The ligand field bands of lanthanide complexes are generally sharper than those of transition metal complexes because
A. transitions are allowed for lanthanide complexes
B. intensity of the bands are higher for lanthanide complexes
C. f-orbital have higher energy than d-orbital
D. f-orbital, compared to d-orbital interact less effectively with ligand
Answer: Option D
Related Questions on Transition Elements
A. Lu3+, Yb3+, Dy3+, Eu3+
B. Eu3+, Dy3+, Yb3+, Lu3+
C. Dy3+, Yb3+, Eu3+, Lu3+
D. Yb3+, Dy3+, Lu3+ , Eu3+
A. D4h and (C2v and C2h)
B. Td and (C2v and D4h)
C. D4h and (C2v and D4h)
D. Td and (C2v and C4v)
The complex that exists as a pair of enantiomers is
A. trans-[CO(H2NCH2CH2NH2)2Cl2]+
B. cis-[Co(NH3)4Cl2]+
C. [Pt(PPh3)(Cl)(Br)(CH3)]-
D. [Co(H2NCH2CH2NH2)3]3+
The complex formed in the brown ring test for nitrates is
A. [Fe(H2O)5NO]3+
B. [Fe(H2O)5NO]2+
C. [Fe(H2O)4(NO)]2+
D. [Fe(H2O)4(NO)]3+
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