The mass of one Avogadro number of helium atom is
A. 1.00 gram
B. 4.00 gram
C. 8.00 gram
D. 4 x 6.02 x 1023 gram
Answer: Option D
Solution (By Examveda Team)
The mass of one Avogadro number of helium atom is 4 x 6.02 x 1023 gram.This Question Belongs to General Knowledge >> Chemistry
Join The Discussion
Comments (4)
Related Questions on Chemistry
Which of the following phenomenon is considered responsible for Global Warming?
A. Greenhouse effect
B. Fire in coal mines
C. Dry farming
D. Monsoon
E. Trade winds
The nucleus of an atom consists of
A. electrons and neutrons
B. electrons and protons
C. protons and neutrons
D. All of the above
The number of moles of solute present in 1 kg of a solvent is called its
A. molality
B. molarity
C. normality
D. formality
The correct ans is 4 gram
The correct ans is 4 gram
number of moles=number of particles/Avogadro's number
Since number of particles =1 Avogadro's number=6.02*10^²³ atoms of He
number of moles=1
Also,number of moles=mass /molar mass
Since n=1,mass=molar mass=4gram
The above given answer is wrong
Correct answer is 4 grm
4 gm is the ans