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The mass of one Avogadro number of helium atom is

This question belongs to General Knowledge Chemistry
Chemistry
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The mass of one Avogadro number of helium atom is

Answer & Solution
Correct Answer: Option D
The mass of one Avogadro number of helium atom is 4 x 6.02 x 1023 gram.
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4 Comments
Taofeeq Osunlaja
Taofeeq Osunlaja 3 years ago
The correct ans is 4 gram
Aifuwa Osamudiamen
Aifuwa Osamudiamen 5 years ago
The correct ans is 4 gram
number of moles=number of particles/Avogadro's number
Since number of particles =1 Avogadro's number=6.02*10^²³ atoms of He
number of moles=1
Also,number of moles=mass /molar mass
Since n=1,mass=molar mass=4gram
Udaibhanu Singh
Udaibhanu Singh 5 years ago
The above given answer is wrong
Correct answer is 4 grm
Sayak Karmakar
Sayak Karmakar 5 years ago
4 gm is the ans
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