The mass of one Avogadro number of helium atom is
A. 1.00 gram
B. 4.00 gram
C. 8.00 gram
D. 4 x 6.02 x 1023 gram
Answer: Option D
Solution(By Examveda Team)
The mass of one Avogadro number of helium atom is 4 x 6.02 x 1023 gram.This Question Belongs to General Knowledge >> Chemistry
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The correct ans is 4 gram
The correct ans is 4 gram
number of moles=number of particles/Avogadro's number
Since number of particles =1 Avogadro's number=6.02*10^²³ atoms of He
number of moles=1
Also,number of moles=mass /molar mass
Since n=1,mass=molar mass=4gram
The above given answer is wrong
Correct answer is 4 grm
4 gm is the ans