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The mass of P4O10 that will be obtained from the reaction of 1.33 gram of P4 and 5.07 of oxygen is
Answer & Solution
Correct Answer:
Option
B
Balanced chemical equation:
P4 + 5O2 --------> P4O10
1 mol 5 mol 1 mol
124g 160g 284g
Here limiting reagent is P4.
So, 124g of P4 produce P4O10 = 284g
Therefore,
1.33g of P4 produce P4O10 = (284/124)*1.33
= 3.05g
P4 + 5O2 --------> P4O10
1 mol 5 mol 1 mol
124g 160g 284g
Here limiting reagent is P4.
So, 124g of P4 produce P4O10 = 284g
Therefore,
1.33g of P4 produce P4O10 = (284/124)*1.33
= 3.05g
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LoginP4 + 5 O2 -> P4O10
1 mol 5 mol 1 mol
124g 160g 284g
Here limiting reagent is P4.
124g of P4 produce P4O10 = 284g
So, 1.33g of P4 produce P4O10 = (284/124)*1.33 = 3.05g