The mass of P4O10 that will be obtained from the reaction of 1.33 gram of P4 and 5.07 of oxygen is
A. 2.05 gram
B. 3.05 gram
C. 4.05 gram
D. 5.05 gram
Answer: Option B
Solution(By Examveda Team)
Balanced chemical equation:P4 + 5O2 --------> P4O10
1 mol 5 mol 1 mol
124g 160g 284g
Here limiting reagent is P4.
So, 124g of P4 produce P4O10 = 284g
Therefore,
1.33g of P4 produce P4O10 = (284/124)*1.33
= 3.05g
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Please explain it
Balance chemical equation
P4 + 5 O2 -> P4O10
1 mol 5 mol 1 mol
124g 160g 284g
Here limiting reagent is P4.
124g of P4 produce P4O10 = 284g
So, 1.33g of P4 produce P4O10 = (284/124)*1.33 = 3.05g
answer with solution???