The maximum value of F in the following equation 5E9 + 2F8 + 3G7 = 1114 is:
A. 8
B. 5
C. 9
D. 7
Answer: Option C
Solution (By Examveda Team)
According to the question,$$\eqalign{ & \,5\,\,\,\,\,E\,\,\,\,\,9 \cr & \,2\,\,\,\,\,F\,\,\,\,\,8 \cr & \,3\,\,\,\,\,G\,\,\,\,\,7 \cr & \underline {\overline {11\,\,\,\,\,1\,\,\,\,\,4\,} } \cr} $$
⇒ Sum of 2, E, F and G must be 11. For maximum F we will have to take E and G zero.
∴ F = 9
This Question Belongs to Arithmetic Ability >> Number System
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