The mean proportional between $$\left( {3 + \sqrt 2 } \right)$$ and $$\left( {12 - \sqrt {32} } \right)$$ is-
A. $$\sqrt 7 $$
B. $${\text{2}}\sqrt 7 $$
C. $${\text{6}}\sqrt 7 $$
D. $$\frac{{15 - 3\sqrt 2 }}{2}$$
Answer: Option B
Solution (By Examveda Team)
Required mean proportional$$\eqalign{ & = \sqrt {\left( {3 + \sqrt 2 } \right)\left( {12 - \sqrt {32} } \right)} \cr & = \sqrt {\left( {3 + \sqrt 2 } \right)\left( {12 - 4\sqrt 2 } \right)} \cr & = \sqrt {36 - 8} \cr & = \sqrt {28} \cr & = 2\sqrt {7} \cr} $$
This Question Belongs to Arithmetic Ability >> Ratio
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