The mean proportional between $$\left( {3 + \sqrt 2 } \right)$$ and $$\left( {12 - \sqrt {32} } \right)$$ is-
A. $$\sqrt 7 $$
B. $${\text{2}}\sqrt 7 $$
C. $${\text{6}}\sqrt 7 $$
D. $$\frac{{15 - 3\sqrt 2 }}{2}$$
Answer: Option B
Solution(By Examveda Team)
Required mean proportional$$\eqalign{ & = \sqrt {\left( {3 + \sqrt 2 } \right)\left( {12 - \sqrt {32} } \right)} \cr & = \sqrt {\left( {3 + \sqrt 2 } \right)\left( {12 - 4\sqrt 2 } \right)} \cr & = \sqrt {36 - 8} \cr & = \sqrt {28} \cr & = 2\sqrt {7} \cr} $$
Related Questions on Ratio
If a : b : c = 3 : 4 : 7, then the ratio (a + b + c) : c is equal to
A. 2 : 1
B. 14 : 3
C. 7 : 2
D. 1 : 2
If $$\frac{2}{3}$$ of A=75% of B = 0.6 of C, then A : B : C is
A. 2 : 3 : 3
B. 3 : 4 : 5
C. 4 : 5 : 6
D. 9 : 8 : 10
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