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The number (248 - 1) is exactly divisible by two numbers between 60 and 70. The numbers are :
Answer & Solution
Correct Answer:
Option
A
(248 - 1)
= [(26)8 - 1]
= (64)8 - 1
When n is even , (xn - an) is completely divisible by both (x - a) and (x + a)
∴ (648 - 18) is divisible by both (64 - 1) and (64 + 1)
⇒ (248 - 1) is divisible by both 63 and 65
= [(26)8 - 1]
= (64)8 - 1
When n is even , (xn - an) is completely divisible by both (x - a) and (x + a)
∴ (648 - 18) is divisible by both (64 - 1) and (64 + 1)
⇒ (248 - 1) is divisible by both 63 and 65
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