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The number (248 - 1) is exactly divisible by two numbers between 60 and 70. The numbers are :

A. 63 and 65

B. 63 and 67

C. 61 and 65

D. 65 and 67

Answer: Option A

Solution(By Examveda Team)

(248 - 1)
= [(26)8 - 1]
= (64)8 - 1
When n is even , (xn - an) is completely divisible by both (x - a) and (x + a)
∴ (648 - 18) is divisible by both (64 - 1) and (64 + 1)
⇒ (248 - 1) is divisible by both 63 and 65

This Question Belongs to Arithmetic Ability >> Number System

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