The number formed from the last two digits (ones and tens) of the expression 212n - 64n , where n is any positive integer is :
A. 10
B. 00
C. 30
D. 02
Answer: Option B
Solution (By Examveda Team)
We have : (212n - 64n)= (212n - 24n × 34n)
= 24n (28n - 34n)
Putting n = 1, we get the number 24 (28 - 34)
= 16 (256 - 81)
= (16 × 175)
= 2800
Hence, the number formed by last two digits is 00
This Question Belongs to Arithmetic Ability >> Number System
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