?
The number formed from the last two digits (ones and tens) of the expression 212n - 64n , where n is any positive integer is :
Answer & Solution
Correct Answer:
Option
B
We have : (212n - 64n)
= (212n - 24n × 34n)
= 24n (28n - 34n)
Putting n = 1, we get the number 24 (28 - 34)
= 16 (256 - 81)
= (16 × 175)
= 2800
Hence, the number formed by last two digits is 00
= (212n - 24n × 34n)
= 24n (28n - 34n)
Putting n = 1, we get the number 24 (28 - 34)
= 16 (256 - 81)
= (16 × 175)
= 2800
Hence, the number formed by last two digits is 00
Join the Discussion
Login to post a comment or share your explanation.
Login