The number nearest to 43582 divisible by each of 25, 50 and 75 is = ?
A. 43500
B. 43550
C. 43600
D. 43650
Answer: Option D
Solution(By Examveda Team)
LCM of 25, 50 and 75 = 150On dividing 43582 by 150, remainder = 82
∴ Required number
= 43582 + (150 – 82)
= 43650
Alternate
LCM of 25, 50 and 75 = 5 × 5 × 2 × 3 = 150
On dividing 43582 by 150, the remainder is 82 and quotient is 290
So, required number
= 150 × 291
= 43650
This Question Belongs to Arithmetic Ability >> Problems On H.C.F And L.C.M
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Comments ( 1 )
Related Questions on Problems on H.C.F and L.C.M
The option (d =43650) is greater than 43582. That is not nearest the number 43582. Because the number 43582 is the nearest 43650. I think, the nearest number will be adjacent to 43582 and less than that. So the correct answer will be option (a)=43582-82)=43500.