Directions (1 - 5): Study the table given below carefully and answer the question that follow:
Number of Athletes (In Hundred) Who Participated In a Sports Event from 5 different Countries Over the Years.
M → Male F → Female
| Country → | A | B | C | D | E | |||||
| Years ↓ | M | F | M | F | M | F | M | F | M | F |
| 2005 | 4.4 | 3.3 | 6.3 | 4.2 | 4.5 | 3.1 | 5.6 | 4.1 | 4.7 | 2.1 |
| 2006 | 6.6 | 4.2 | 8.4 | 6.2 | 6.9 | 3.3 | 8.4 | 6.3 | 7.8 | 5.2 |
| 2007 | 4.6 | 1.8 | 7.4 | 4.8 | 4.8 | 2.8 | 9.3 | 7.3 | 8.7 | 6.5 |
| 2008 | 9.6 | 4.9 | 11.4 | 8.4 | 6.6 | 4.2 | 12.6 | 9.4 | 8.9 | 5.8 |
| 2009 | 11.8 | 6.4 | 10.6 | 5.2 | 7.9 | 6.3 | 14.4 | 10.2 | 11.8 | 9.2 |
| 2010 | 8.2 | 5.2 | 6.4 | 7.2 | 10.8 | 6.9 | 15.6 | 12.1 | 13.6 | 9.8 |
The number of female athletes who participated from Country E in the year 2009 was approximately what percentage of the total number of athletes who participated from Country B in the year 2008?
A. 40%
B. 46%
C. 50%
D. 56%
E. 60%
Answer: Option B
Solution(By Examveda Team)
Number of female athletes from E in 2009= 9.2 × 100
= 920
Total number of athletes from B in 2008
= (11.4 + 8.4) × 100
= 19.8 × 100
= 1980
Let 920 = x% of 1980
Then,
$$\eqalign{ & \Rightarrow \frac{x}{100}\times1980 = 920 \cr & \Rightarrow x = \frac{920 × 100}{1980} \cr & \,\,\,\,\,\,\,\,\, = \frac{4600}{99}\% \cr & \,\,\,\,\,\,\,\,\, = 46.46\% \cr & \,\,\,\,\,\,\,\,\, \approx 46\% \cr} $$
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