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The number of numbers from 1 to 200 which are divisible by neither 3 nor 7 is :

A. 115

B. 106

C. 103

D. less than 100

Answer: Option A

Solution(By Examveda Team)

The required number = Number of numbers, which are (divisible by 3 + divisible by 7 - divisible by 21)
Number of number divisible by 3,
$$\eqalign{ & {\text{ = }} {\frac{{ {198 - 3} }}{3}} + 1 \cr & = 66 \cr} $$
Number of number divisible by 7
$$\eqalign{ & = {\frac{{ {196 - 7} }}{7}} + 1 \cr & = 28 \cr} $$
Number of number divisible by 21,
$$\eqalign{ & = {\frac{{ {189 - 21} }}{{21}}} + 1 \cr & = 9 \cr} $$
Thus, the divisible value
$$\eqalign{ & = {66 + 28 - 9} \cr & = 85 \cr} $$
Thus, number of numbers which are not divisible by 3 or 7
$$\eqalign{ & = {\text{ }}200{\text{ }} - {\text{ }}85 \cr & = {\text{ }}115 \cr} $$

This Question Belongs to Arithmetic Ability >> Number System

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