The number of oranges in three basket are in the ratio 3 : 4 : 5. In which ratio the no. of oranges in first two basket must be increased so that the new ratio becomes 5 : 4 : 3 ?
A. 3 : 4
B. 2 : 3
C. 1 : 3
D. 2 : 1
E. None of these
Answer: Option D
Solution(By Examveda Team)
Let, B1 : B2 : B3 = 3x : 4x : 5x andB1 : B2 : B3 = 5y : 4y : 3y
Number of oranges remain constant in third basket as increase in oranges takes place only in first two baskets.
Hence, 5x = 3y x = $$\frac{3y}{5}$$ and, ∴ 3x : 4x : 5x (putting the vale of x)
= $$\frac{{9{\text{y}}}}{5}:\frac{{{\text{12y}}}}{5}:\frac{{{\text{15y}}}}{5}$$
= 9y : 12y : 15y
And,
5y : 4y : 3y (multiple by 5) → 25y : 20y : 15y
∴Increment in first basket = 16 And, Increment in second basket = 8 Thus, Required ratio = $$\frac{{16}}{8}$$ = 2 : 1
This Question Belongs to Arithmetic Ability >> Ratio
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Related Questions on Ratio
If a : b : c = 3 : 4 : 7, then the ratio (a + b + c) : c is equal to
A. 2 : 1
B. 14 : 3
C. 7 : 2
D. 1 : 2
If $$\frac{2}{3}$$ of A=75% of B = 0.6 of C, then A : B : C is
A. 2 : 3 : 3
B. 3 : 4 : 5
C. 4 : 5 : 6
D. 9 : 8 : 10
The original ratio is 3:4:5
Now the new ratio is 5:4:3
to compare the ratios, try to make the third component of each equal. Thus,
9:12:15
25:20:15
now you can see the change.
16 and 8. SO the ratio of increment= 2:1
Original ratio is 3:4:5
Revised ratio is 5:4:3
Make the third component equal in both ratios :
Original ratio = 9:12:15
Revised ratio = 25:20:15
=> increase in First basket = 25 - 9 = 16
increase in second basket = 20 - 12 = 8
Required ratio = 16:8 = 2:1
Udayan Gharam why did u multilply the equation with 3 and 5 ?
I didn't get this solution plz explain in detail
(3:4:5)*3=9:12:15
(5:4:3)*5=25:20:15
ratio=25-9:20-12=16:8=2:1
i didn't get this solution