The number of zeros at the end of 60! is :

A. 12

B. 14

C. 16

D. 18

Answer: Option B

Solution(By Examveda Team)

Clearly, highest power of 2 is much higher as compared to that of 5 in 60!,
So, Required number of zeros
= Highest power of 5
= $$ \left[ {\frac{{60}}{5}} \right] + \left[ {\frac{{60}}{{{5^2}}}} \right]$$
= 12 + 2
= 14