The numbers of students in section A and section B of a class are 50 and 62, respectively. The average score in mathematics of all students is 75. If the average score of students in section A is 20% more than that of students in section B, then what is the average score of students in section A (correct to one decimal place)?
A. 85.7
B. 87.5
C. 82.6
D. 84.3
Answer: Option C
Solution (By Examveda Team)
20% = $$\frac{1}{5}$$Let, average marks of section B = 5x
Average marks of section A = 6x
Total marks = 50 × 6x + 62 × 5x = (50 + 62)
300x + 310x = 112 × 75
610x = 8400
x = $$\frac{{840}}{{61}}$$
Average marks of section A students = 6x
= 6 × $$\frac{{840}}{{61}}$$
= 82.6
This Question Belongs to Arithmetic Ability >> Average
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